/b/ - >g1 ◦f = g2 ◦f =⇒g1 = g2 ok now this is epic

Anonymous 30/08/2026, 16:59:45 No.332087

>g1 ◦f = g2 ◦f =⇒g1 = g2
ok now this is epic

Anonymous 30/08/2026, 18:06:56 No.332090

>>332087 (OP) 
Other possibilities is that f is an annihilator for ◦ operator, or that involved constituents are complex.

Replies: >>332120

Anonymous 31/08/2026, 05:05:08 No.332120

>>332087 (OP) 
>>332090
?

/b/ - Random